Weight Balance CodeChef Solution

Problem

No play and eating all day makes your belly fat. This happened to Chef during the lockdown. His weight before the lockdown was w

 kg (measured on the most accurate hospital machine) and after M months of lockdown, when he measured his weight at home (on a regular scale, which can be inaccurate), he got the result that his weight was w_2 kg (w_2 \gt w_1).


w_1

Scientific research in all growing kids shows that their weights increase by a value between x_1 and x_2 kg (inclusive) per month, but not necessarily the same value each month. Chef assumes that he is a growing kid. Tell him whether his home scale could be giving correct results.

Input

  • The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.
  • The first and only line of each test case contains five space-separated integers w_1w_2x_1x_2 and M.

Output

For each test case, print a single line containing the integer 1 if the result shown by the scale can be correct or 0 if it cannot.

Constraints

  • 1 \leq T \leq 10^5
  • 1 \leq w_1 \lt w_2 \leq 100
  • 0 \leq x_1 \leq x_2 \leq 10
  • 1 \leq M \leq 10

Sample 1:

Input
Output
5
1 2 1 2 2
2 4 1 2 2
4 8 1 2 2
5 8 1 2 2
1 100 1 2 2
0
1
1
1
0

Explanation:

Example case 1: Since the increase in Chef's weight is 2 - 1 = 1 kg and that is less than the minimum possible increase 1 \cdot 2 = 2 kg, the scale must be faulty.

Example case 2: Since the increase in Chef's weight is 4 - 2 = 2 kg, which is equal to the minimum possible increase 1 \cdot 2 = 2 kg, the scale is showing correct results.

Example case 3: Since the increase in Chef's weight is 8 - 4 = 4 kg, which is equal to the maximum possible increase 2 \cdot 2 = 4 kg, the scale is showing correct results.

Example case 4: Since the increase in Chef's weight 8 - 5 = 3 kg lies in the interval [1 \cdot 2, 2 \cdot 2] kg, the scale is showing correct results.

Example case 5: Since the increase in Chef's weight is 100 - 1 = 99 kg and that is more than the maximum possible increase 2 \cdot 2 = 4 kg, the weight balance must be faulty.

ANSWER


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